What regex to use for ^\s* function?

[nycdude]

Hello,

I'm trying to find/replace with regex all the blank spaces and lines of a variable and remove them with replacing with nothing. I'm using text processing for the variable and I'm using regex that works in the regex builder and online regex testers and notepad++ too.

But it won't work in ZP, is there a better way? It kind of worked on only one line (see pic).

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It won't get the rest blank lines and and blank spaces before text

Thank you

 

[LmPopo]

But it won't work in ZP, is there a better way? It kind of worked on only one line

(?m)^\s*

 

[nycdude]

(?m)^\s*

Yes! That worked thank you very much. Now I realize there's blank spaces after the lines of text, anyway to trim that off too?

Really appreciate the help.
Also, is there any special reference for ZP regex? Seems it's different to me from regex I'm used to with notepad++.

 

[LmPopo]

Now I realize there's blank spaces after the lines of text, anyway to trim that off too?

(?m)^\s*|[\ \f\t\v]*(?=[\r\n]*$)

Also, is there any special reference for ZP regex?

Seems no