How To Pass Variable in List File Path Name?

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Maroso

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I have a multi level scraping project and a I want to save each level data to a file. For easier template building I chose to create a variable with each level of scraping and after that pass that variable to list file path.

Problem is that zenno doesn't save the files with variable for level. The only way to accomplish this is by saving scraping data to a file directly and there we can process the variable in file name but we can't use the list remove duplicate lines and filtering using regex.

Any suggestion?

I uploaded the template for more info
 

Вложения

PS: test was done in project maker with zenno version v.5.12.0.0
 
When you set Load list from file in list settings, list binds to file at project start and will be kept during whole project.
If you would like to dynamically save list to file in your project, you should use List processing>Save to file operation.
It goes like this:
 

Вложения

  • Спасибо
Реакции: Maroso
Nice and smart way to do it, thanks again @VladZen , works perfectly
 
  • Спасибо
Реакции: VladZen

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