Returning C# results

Phoenix78 · 19.11.2022

You can try to do the following example

https://zennolab.com/discussion/threads/kak-zapuskat-komandnuju-stroku-cmd.19634/post-431794

BAZAg · 19.11.2022

Perhaps if you just submit a string - it will not work. I didn't check.

C#:

string program = @"""C:\Program Files\Stringing\stringy.exe""";
string filename = Path.Combine(@"E:\RAW", project.Variables["FileName"].Value);
string metaJSON = Path.Combine(@"E:\RAW", project.Variables.UID.json); // json variable
string thumbnail = Path.Combine(@"E:\RAW", project.Variables["Image"].Value);
List<string[]> list = new List<string[]>();

list.Add(new[]{"-filename",string.Format(@"""{0}""", filename) });
list.Add(new[]{"-metaJSON",string.Format(@"""{0}""", metaJSON) });
list.Add(new[]{"-thumbnail",string.Format(@"""{0}""", thumbnail) });

string line = string.Join(", ", new[]{program, string.Join(" ", list.Select(x=> string.Join(" ", x)))});
// return line; // arguments line

Process P = Process.Start(line);
P.WaitForExit();
int result = P.ExitCode;

The second example below is more like a working example.

C#:

string program = @"""C:\Program Files\Stringing\stringy.exe""";
string filename = Path.Combine(@"E:\RAW", project.Variables["FileName"].Value);
string metaJSON = Path.Combine(@"E:\RAW", project.Variables.UID.json); // json variable
string thumbnail = Path.Combine(@"E:\RAW", project.Variables["Image"].Value);
List<string[]> list = new List<string[]>();

list.Add(new[]{"-filename",string.Format(@"""{0}""", filename) });
list.Add(new[]{"-metaJSON",string.Format(@"""{0}""", metaJSON) });
list.Add(new[]{"-thumbnail",string.Format(@"""{0}""", thumbnail) });

//string line = string.Join(", ", new[]{program, string.Join(" ", list.Select(x=> string.Join(" ", x)))});
// return line; // arguments line


Process process = new Process();
process.StartInfo.FileName = program;
process.StartInfo.Arguments = string.Join(" ", list.Select(x=> string.Join(" ", x)));
process.StartInfo.Verb = "runas"; // admin
process.StartInfo.CreateNoWindow = false;// window hide
process.Start();    
process.WaitForExit();

BAZAg · 19.11.2022

PHaRTnONu сказал(а):
this didnt work? am i able to pass a value through this?

:/
This i though would work
{-Variable.UID-}
was just supposed to have a .json on the end of that variable.
i tried setting the variable {-Variable.Json-} Посмотреть вложение 99789
and
string metaJSON = Path.Combine(@"E:\RAW", project.Variables.["Json"].Value);

but im getting
Посмотреть вложение 99790

Run in a new template. Perhaps the error is in another cube.

Good line.
This line contains no errors.
string metaJSON = Path.Combine(@"E:\RAW", project.Variables["Json"].Value);

Yes ERROR - DOT before ["Json"]

string metaJSON = Path.Combine(@"E:\RAW", project.Variables.["Json"].Value);
Show the topmost error in the log.
Before execution, clear the log.

BAZAg · 19.11.2022

PHaRTnONu сказал(а):
it was the . Right after . Variables
removed it now have this error

Compiling code of Error in action "CS0246" "The type or namespace name 'Process' could not be found (are you missing a using directive or an assembly reference?)". [Row: 15; Column: 1]
Посмотреть вложение 99792

The error message says that you did not add using.
Try adding the full path like this:

C#:

// Process process = new Process();
System.Diagnostics.Process process = new System.Diagnostics.Process();

BAZAg · 19.11.2022

PHaRTnONu сказал(а):
that worked, except im just getting the return of "ok" which isnt the return value the cmd is supposed to give a result

C#:

string program = @"""C:\Program Files\Stringing\stringy.exe""";
string filename = Path.Combine(@"E:\RAW", project.Variables["FileName"].Value);
string metaJSON = Path.Combine(@"E:\RAW", project.Variables["Json"].Value);
string thumbnail = Path.Combine(@"E:\RAW", project.Variables["Image"].Value);

var list = new List<string[]>();
    list.Add(new[]{"-filename",string.Format(@"""{0}""", filename) });
    list.Add(new[]{"-metaJSON",string.Format(@"""{0}""", metaJSON) });
    list.Add(new[]{"-thumbnail",string.Format(@"""{0}""", thumbnail) });


string out_line = string.Empty;
try {
    var p = new System.Diagnostics.Process();
    p.StartInfo.RedirectStandardError = true;
    p.StartInfo.RedirectStandardOutput = true;
    p.StartInfo.UseShellExecute = false;
    p.StartInfo.CreateNoWindow = true;
    p.StartInfo.Verb = "runas";
    p.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
    p.StartInfo.FileName = program; // path program
    p.StartInfo.Arguments = string.Join(" ", list.Select(x=> string.Join(" ", x))); // args
    p.OutputDataReceived += new System.Diagnostics.DataReceivedEventHandler((sender, e) => {
        if(!string.IsNullOrEmpty(e.Data)){
            out_line = e.Data;
        }
    });
    p.ErrorDataReceived += new System.Diagnostics.DataReceivedEventHandler((sender, e) => {
        if(!string.IsNullOrEmpty(e.Data)){
            out_line = e.Data;
        }
    });
    p.Start();
    p.BeginOutputReadLine();
    p.BeginErrorReadLine();
    p.WaitForExit();
}
catch (Exception e){
    out_line = e.Message;
}

return out_line;

Поиск

Returning C# results

PHaRTnONu

Client

PHaRTnONu

Client

Phoenix78

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BAZAg

Client

PHaRTnONu

Client

Вложения

BAZAg

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PHaRTnONu

Client

BAZAg

Client

PHaRTnONu

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BAZAg

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PHaRTnONu

Client

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