How to Do Random Birthday in 01/12/1990 Format

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JD123

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I know how to do a random number between 1940 and 1990 for example but not sure how to do random birthday numbers for a format like 04/06/1960. It's not a drop down box just an input area. Any Ideas?
 
{-Random.Int-|-10-|-29-}/{-Random.Int-|-1-|-10-}/{-Random.Int-|-1940-|-1960-}
 
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ahh duh, ya that's easy. THanks for the quick response. How about doing a random birthday on a drop down box, I haven't done that before?
 
you are welcome, mate. it is also easy
the same way.
{-Random.Int-|-1-|-13-} to choose a month for example
for year dropdown box usually looks like 2011,2010....etc
to choose from here you should use {-Random.Int-|-18-|-80-} for example,
in this case you'll get a year from 1931 till 1993
 
So right now I just picked 1 year and it says SET value 60, so I would just change Attribute Value to {-Random.Int-|-18-|-80-} for example? Or however many drop down numbers they have?
 
Yes you can set up value using a macro random there.
 

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