L Lannister Client Регистрация 28.08.2011 Сообщения 19 Благодарностей 2 Баллы 0 13.06.2012 #1 hi, how to do that in ZP4 : {-File.GetString-|-{-Directory.RandomFile-|-\Resources\-}-|-random-|-true-} ZP4 is become so complicated :/ thanks !
hi, how to do that in ZP4 : {-File.GetString-|-{-Directory.RandomFile-|-\Resources\-}-|-random-|-true-} ZP4 is become so complicated :/ thanks !
lupo Client Регистрация 28.05.2012 Сообщения 72 Благодарностей 32 Баллы 18 13.06.2012 #2 Here it is P.S. I'm sure that there is much better way to do it, but this works also Вложения random-line-from-random-file.rar 15,1 КБ Просмотры: 509 Реакции: Lannister
L Lannister Client Регистрация 28.08.2011 Сообщения 19 Благодарностей 2 Баллы 0 13.06.2012 #3 Thank you for your help but it does not delete the line in the file. If i want to do that i need to take the content of the file & delete it, get a random line, and write a new file with the new content. that's a lot of blocks :/
Thank you for your help but it does not delete the line in the file. If i want to do that i need to take the content of the file & delete it, get a random line, and write a new file with the new content. that's a lot of blocks :/
rostonix Известная личность Регистрация 23.12.2011 Сообщения 29 067 Благодарностей 5 715 Баллы 113 13.06.2012 #4 You create a list In list properties set the text file to sync with. Then use action Operations with lists - Get line Реакции: Lannister
You create a list In list properties set the text file to sync with. Then use action Operations with lists - Get line
L Lannister Client Регистрация 28.08.2011 Сообщения 19 Благодарностей 2 Баллы 0 13.06.2012 #5 Thanks it works, in the file path of the list i set : {-Directory.RandomFile-|-{-Project.Directory-}\files-} ,(I did not think it would work -_-)
Thanks it works, in the file path of the list i set : {-Directory.RandomFile-|-{-Project.Directory-}\files-} ,(I did not think it would work -_-)