How to Remove elements from ListA that can be found on ListB

[Emp1]

Hi,

I know, i am not yet client and I already ask question.
I am enjoying 14d trial and want to try the software a little bit more before I buy.

So, lets test the Zenno community, can you answer this question:

How can you remove elements from a list that already exist in another?

[table="width: 400, class: grid"]
[tr]
[td]ListA[/td]
[td]ListB[/td]
[/tr]
[tr]
[td]Alan[/td]
[td]Rika[/td]
[/tr]
[tr]
[td]Alpha[/td]
[td]Binaou[/td]
[/tr]
[tr]
[td]Activia[/td]
[td]Alan[/td]
[/tr]
[/table]


How to remove Alan from list B ?

I can not do it

PS : list are dynamic: Alan, Rika, etc... are fake data created to illustrate my question.

Thank you very much.

 

[bigcajones]

Посмотреть вложение RegexDelete.xmlz

 

[Emp1]

Thank bigcajones

Better logic than myself
It remind me ti83+ programming architecture.

Thank you very much

 

[bigcajones]

Any time.

 

[Emp1]

I am now a client. Thank you very much