You need to create a control, something like this:
Код:
int i = 0;
try{
i = project.Context["i"];
}
catch{
project.Context["i"] = i;
}
if (i < 20){
System.Threading.Thread.Sleep(2000);
}
else{
throw new Exception();
}
i += 1;
project.Context["i"] = i;
That code will try check element 20 times and if there is no sucess, it will move to timeout block.
I'm not sure to understand the logic here, it seems to be in an infinite loop.
If the action is Ok, it come back to the action again and again, and if not it goes to timeout.
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EtaLasquera
reply is extremely good for a lot of case's but i don't think that was the question you were asking
For a 'GENERAL' time out for some action blocks you need to go into the "action properties"
(double click or in the action properties windows there are sometimes a tab thats says "MORE")
EtaLasquera
reply is extremely good for a lot of case's but i don't think that was the question you were asking
For a 'GENERAL' time out for some action blocks you need to go into the "action properties"
(double click or in the action properties windows there are sometimes a tab thats says "MORE")