Possible to generate Codes with an Pattern?

[Ehnoah]

Hey,

I currently using the random Function to generate Codes, but the COdes using Patterns, so I am curious, if that might work?

ABCDEF-123-ABCDEF-123
(First ABCDEF must contain an U and A)
(Secound ABCDEF must contain an O and E)

Is this somehow possible with the Random Function? Or is own C# COde required?

Thanks <3

 

[lokiys]

Hi, this does not help? You can pick any custom characters you want.

 

[Ehnoah]

That will only use this Characters no?

For example the Charset is:

AFGJMPU But the Code always require an F

So FXXXX or XXFXXX or XFXXXX (so a F is required) Not sure if this is suposed to work. Is this Screen you showed actually ZennoPoster 7? Because I used C# for the Generation now, I never saw this UI you posted.

 

[lokiys]

That will only use this Characters no?

For example the Charset is:

AFGJMPU But the Code always require an F

So FXXXX or XXFXXX or XFXXXX (so a F is required) Not sure if this is suposed to work. Is this Screen you showed actually ZennoPoster 7? Because I used C# for the Generation now, I never saw this UI you posted.

Yes, this is Random action properties. Using c# is fine also if You can write it.

 

[Ehnoah]

Nah I just copied a code snipped xD

 

[kingbin]

This is very simple with C#. Althrough you can made it with Zenno Function but it need you more step. This is my example with the first which must have U and A

 

[Ehnoah]

Hey thanks for the Demo, I see your attempt, sadly the Code gets pretty long, it should be limited to 6 chars.

So

XXXUXA-123-OXXEXX-123

So first Part is 6 Chars and 2. part is 6 chars.

 

[kingbin]

Hey thanks for the Demo, I see your attempt, sadly the Code gets pretty long, it should be limited to 6 chars.

So

XXXUXA-123-OXXEXX-123

So first Part is 6 Chars and 2. part is 6 chars.

Ah see your question and only that need have 2 character. Here is demo2, which make full text 4 part, limit 6 char and must have some char.
P/s: Char random can be duplicate, example in 6 char have 2 "A" or something. If you need it not duplicate, you need some other logic to check duplicate or another mindset

 

[Ehnoah]

That does the Job and I got the Logic, thanks <3